# Question #719a9

##### 1 Answer

Mar 16, 2016

#### Explanation:

- Take the balanced equation;

#2KHCO_3->K_2CO_3+H_2CO_3# - Take the molar masses of
#KHCO_3# and#K_2CO_3# - Compute stoichiometrically, starting with the mass of
#KHCO_3#

#1.6cancel(g KHCO_3) # x# (1 cancel(mol KHCO_30)/(cancel(100g KHCO_3)) # x# (1 cancel(mol K_2CO_3))/(2 cancel(mol KHCO_3)) # x# (138g K_2CO_3)/(1 cancel(mol K_2CO_3))# - The answer is
#1.104# g#K_2CO_3# - To compute the atual yield, use the formula:

#% yield=(actual yield)/(theo yield)# , rearrange and plug in values to the derived formula;

#actual yied=(% yield)(theo yield)# - The actual yield is
#1.0156g# #K_2CO_3#