Question 44937

Oct 8, 2016

69.69% K, 28.52%O, 1.79% H

Explanation:

Find the molecular mass of the whole compound:
$A M \left(K\right) = 39.1 A M U$
$A M \left(O\right) = 16.00 A M U$
$A M \left(H\right) = 1.008 A M U$
$39.1 + 16 + 1.008 = 56.108$

Find the percentage of each element within the compound:
%(K)=100x39.1/56.108=69.69%
%(O)=100x16/56.108=28.52%
%(H)=100x1.008/56.108=1.79%#