Question

Question #bf524

Answer 1

You will need to supply 4.8 GJ of heat energy.

The equation for the reaction is

`"CaCO"_3 → "CaO" + "CO"_2`; `Δ_rH = "+179 kJ"//"mol"`

Step 1. Convert the mass of `"CaCO"_3` to moles.

`2.7 × 10^3 color(red)(cancel(color(black)("kg CaCO"_3))) × ("1 kmol CaCO"_3)/(100.09 color(red)(cancel(color(black)("kg CaCO"_3)))) = "27.0 kmol CaCO"_3`

Step 2. Calculate the amount of heat required.

`27.0 color(red)(cancel(color(black)("kmol CaCO"_3))) × "179 MJ"/(1 color(red)(cancel(color(black)("kmol CaCO"3)))) = "4800 MJ" = "4.8 GJ"`