# Question #575a0

Mar 24, 2016

We can use the Ideal Gas Law, $P V = n R T$. Rearranging, $\frac{n}{V} = \frac{P}{R T} = \frac{112.6}{0.082 \times 293} = 4.7$.

This answer is in $m o l {L}^{-} 1$, and each mole of ${H}_{2}$ is $2$ $g$, so the final answer is $9.4$ $g {L}^{-} 1$.

#### Explanation:

Conversions:

${20}^{o} C = 293$ $K$

$1655$ psi = $112.6$ atm

Constant:

0.082 $L a t m {K}^{-} 1 m o {l}^{-} 1$