# How many chromium atoms in a 5.67*g mass of chromium metal?

May 3, 2016

In $5.67 \cdot g$ chromium metal?

#### Explanation:

The molar mass of elemental chromium is $52.00 \cdot g \cdot m o {l}^{-} 1$. What does this mean? It means that if there are $52.00 \cdot g$ of chromium metal, there are $\text{Avogadro's number}$ of chromium atoms, i.e. ${N}_{A}$ chromium atoms, or $6.022 \times {10}^{23}$ individual atoms.

Here, I have used ${N}_{A}$ as I would a dozen, or a score, or a gross, or any other collective number.

So the number of atoms?

$\frac{5.67 \cdot g}{52.00 \cdot g \cdot m o {l}^{-} 1} \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$ $=$

$\text{How many chromium atoms?}$