Question #e94ae

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Answer 1 · 2018-02-03T11:45:44

#6# metres.

Preparing a #1# metre wall costs #rarr# Rs. #1.35#

So, It will cost Rs. #340.20# to prepare walls of total #340.2/1.35# #m^2# = #252# #m^2#

So, The total area of the walls = #252# #m^2#

And It costs Rs. #0.85# for matting a floor of #1# #m^2#.

So, It costs Rs. #91.8# for matting a floor of #91.8/0.85# #m^2# = #108# #m^2#

We are given the length of the room is = #12# metres.

So, the width of the room is #108/12# metres = #9# metres.

Now, Let's assume that the height of the room is #h# metres.

Now, According to the problem,

#2(12 + 9) xx h = 252# [The total surface area formula]

#rArr 2(21) xx h = 252#

#rArr 42h = 252#

#rArr h = 252/42 = 6#

So, The height of the room is #6# metres.

Hence Explained.