# If the pressure is reported as 750*mm*Hg, what is the pressure in atmospheres?

Apr 12, 2016

$1$ $a t m$ $\equiv$ $760$ $m m$ $H g$

#### Explanation:

It makes sense to preconvert the pressure measurement ot atmospheres. So ${P}_{1}$ $=$ $\frac{750 \cdot m m \cdot H g}{760 m m \cdot H g \cdot a t {m}^{-} 1}$ $=$ ?? $a t m$

Since amount of gas is constant, use the combined gas law $\frac{{P}_{1} {V}_{1}}{T} _ 1$ $=$ $\frac{{P}_{2} {V}_{2}}{T} _ 2$, and solve for ${V}_{2}$.

You are only justified in quoting an answer to 1 decimal place, as this was the accuracy of the initial conditions.