If the pressure is reported as $750mmHg$ , what is the pressure in atmospheres?

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Answer 1 · 2016-04-12T07:35:53

$1$ $atm$ $-=$ $760$ $mm$ $Hg$

It makes sense to preconvert the pressure measurement ot atmospheres. So $P_1$ $=$ $(750*mm*Hg)/(760mm*Hg*atm^-1)$ $=$ $??$ $atm$

Since amount of gas is constant, use the combined gas law $(P_1V_1)/T_1$ $=$ $(P_2V_2)/T_2$ , and solve for $V_2$ .

You are only justified in quoting an answer to 1 decimal place, as this was the accuracy of the initial conditions.

If the pressure is reported as 750*mm*Hg750*mm*Hg, what is the pressure in atmospheres?