If the pressure is reported as $750 \cdot m m \cdot H g$ $750mmHg$ , what is the pressure in atmospheres?

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If the pressure is reported as $750 \cdot m m \cdot H g$ $750mmHg$ , what is the pressure in atmospheres?

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Answer 1 · 2016-04-12T07:35:53

$1$ $1$ $a t m$ $atm$ $\equiv$ $-=$ $760$ $760$ $m m$ $mm$ $H g$ $Hg$

Explanation:

It makes sense to preconvert the pressure measurement ot atmospheres. So $P_{1}$ $P_1$ $=$ $=$ $\frac{750 \cdot m m \cdot H g}{760 m m \cdot H g \cdot a t m^{- 1}}$ $(750*mm*Hg)/(760mm*Hg*atm^-1)$ $=$ $=$ $? ?$ $??$ $a t m$ $atm$

Since amount of gas is constant, use the combined gas law $\frac{P_{1} V_{1}}{T_{1}}$ $(P_1V_1)/T_1$ $=$ $=$ $\frac{P_{2} V_{2}}{T_{2}}$ $(P_2V_2)/T_2$ , and solve for $V_{2}$ $V_2$ .

You are only justified in quoting an answer to 1 decimal place, as this was the accuracy of the initial conditions.

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If the pressure is reported as $750 \cdot m m \cdot H g$ $750mmHg$ , what is the pressure in atmospheres?

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If the pressure is reported as $750 \cdot m m \cdot H g$ $750mmHg$ , what is the pressure in atmospheres?