What is the conjugate base of oxalic acid, HO(O=)C-C(=O)OH?

May 4, 2016

The conjugate base of oxalic acid is $H O \left(O =\right) C - C \left(= O\right) {O}^{-}$

Explanation:

The conjugate base of any acid, $H A$, is the original acid LESS a proton, ${H}^{+}$. As for any chemical reaction, mass and charge are conserved. Therefore the conjugate base of $H A$ is ${A}^{-}$.

Here we start with a (potential) diacid, $H O \left(O =\right) C - C \left(= O\right) O H$, oxalic acid. So we remove a proton, and get $H O \left(O =\right) C - C \left(= O\right) {O}^{-}$. The conjugate base of this species is ""^(-)O(O=)C-C(=O)O^-, oxalate anion.

May 4, 2016

$H O O C . C O {O}^{-}$

Explanation:

If it represnts the molecular formula of oxalic acld $H O O C . C O O H$.Its conjugate base is the anion formed due to release of proton ${H}^{+}$.
So the conjugate base is $H O O C . C O {O}^{-}$