# What is the conjugate base of "bisulfite ion", HSO_3^(-)?

For bisulfite, $H S {O}_{3}^{-}$, the conjugate base is sulfite ion, $S {O}_{3}^{2 -}$.
Sulfur dioxide dissolved in water gives sulfurous acid, ${H}_{2} S {O}_{3}$. The conjugate base of this material is the original less a proton, i.e. $H S {O}_{3}^{-}$, and the conjugate base of this material is $S {O}_{3}^{2 -}$.