# If pH=0.325 for an aqueous solution, what is [HO^-]?

Jul 21, 2017

$\left[H {O}^{-}\right] \cong 3 \times {10}^{-} 14 \cdot m o l \cdot {L}^{-} 1$. The low $p H$ specifies AN ACIDIC solution....

#### Explanation:

${K}_{w} = {10}^{-} 14 = \left[{H}_{3} {O}^{+}\right] \left[H {O}^{-}\right]$ under standard conditions of $298 \cdot K$ and (near to) $1 \cdot a t m$ pressure.........

It is usually simpler to convert this $p H$ and $p O H$ values than pfaff about with exponential products........

$14 = p H + p O H$; $p H = - {\log}_{10} \left(0.325\right) = 0.488$; and $p O H = 13.51$..

[HO^-]=10^(-13.51)*mol*L^-1=??*mol*L^-1