# A gas enclosed in a piston that has a volume of 245*mL at 0 ""^@C, will express what volume at 95 ""^@C?

Apr 18, 2016

At constant pressure, ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

#### Explanation:

The above was simply a restatement of Charles' Law.

Given your problem, and converting the temperatures to absolute values:

${V}_{2} = {T}_{2} \times {V}_{1} / {T}_{1}$ $=$ $\left(273 + 95\right) \cdot K \times \frac{245 \cdot m L}{\left(273 + 18\right) \cdot K}$ $\cong 300 \cdot m L$

Note that for these problems I am obliged to turn temperatures into absolute temperatures (why? because the Gas Laws assume absolute temperatures). I am NOT obliged to use standard volumes if I am consistent - I could have used pints and gills if I knew what they meant! Thus a measurement in millilitres is quite acceptable.