Question

A gas enclosed in a piston that has a volume of `245*mL` at `0` `""^@C`, will express what volume at `95` `""^@C`?

Answer 1

At constant pressure, `V_1/T_1=V_2/T_2`

Explanation:

The above was simply a restatement of Charles' Law.

Given your problem, and converting the temperatures to absolute values:

`V_2=T_2xxV_1/T_1` `=` `(273+95)*Kxx(245*mL)/((273+18)*K)` `~=300*mL`

Note that for these problems I am obliged to turn temperatures into absolute temperatures (why? because the Gas Laws assume absolute temperatures). I am NOT obliged to use standard volumes if I am consistent - I could have used pints and gills if I knew what they meant! Thus a measurement in millilitres is quite acceptable.