Question #068f6

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Question #068f6

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Answer 1 · 2016-07-28T11:20:29

${1.2}^{3} = 1.728$ $1.2^3 = 1.728$

Explanation:

We would do this in exactly the same way as if we we had variables.

$x^{5} \times x^{- 2} = x^{5 - 2} = x^{3} or x^{5} \times x^{- 2} = \frac{x^{5}}{x^{2}} = x^{3}$ $x^5 xx x^-2 = x^(5-2) = x^3" or "x^5 xx x^-2 = x^5/x^2 = x^3$

If the bases are the same and you are multiplying, ADD the indices.

${1.2}^{5} \times {1.2}^{- 2} = {1.2}^{5 - 2} = {1.2}^{3}$ $1.2^5 xx 1.2^-2 = 1.2^(5-2) = 1.2^3$

This can be calculated to give $1.728$ $1.728$

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Question #068f6

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