# Question c729d

Apr 30, 2016

Here's what I got.

#### Explanation:

As you know, a Bronsted-Lowry acid is characterized by the fact that it can act as a proton donor. Likewise, a Bronsted-Lowry base is characterized by the fact that it can accept a proton.

A proton, ${\text{H}}^{+}$, is simply the nucleus of a hydrogen atom, $\text{H}$.

In a given chemical reaction, you can identify a Bronsted-Lowry acid by looking for the chemical species that loses a proton. Consequently, the chemical species that accepts the proton lost by a Bronsted-Lowry acid will act as a Bronsted-Lowry base.

Now, the chemical species that is left behind after an acid donates a proton is called a conjugate base because it can accept a proton to reform the original acid.

Likewise, the chemical species that is formed when a base accepts a proton is called a conjugate acid because it can donate this proton to reform the original base.

color(red)("H")"NO"_ (3(aq)) + "SO"_ (4(aq))^(2-) -> color(red)("H")"SO"_ (4(aq))^(-) + "NO"_(3(aq))^(-)

Here ${\text{HNO}}_{3}$ donates its proton to ${\text{SO}}_{4}^{2 -}$, which accepts it to form ${\text{HSO}}_{4}^{-}$.

As a result, you can say that ${\text{HNO}}_{3}$ acts as an acid and ${\text{SO}}_{4}^{2 -}$ acts as a base.

overbrace(color(red)("H")"NO"_ (3(aq)))^(color(purple)("acid")) + overbrace("SO"_ (4(aq))^(2-))^(color(green)("base")) -> color(red)("H")"SO"_ (4(aq))^(-) + "NO"_(3(aq))^(-)#

Now, ${\text{HNO}}_{3}$, which is called nitric acid, donates its proton to leave behind the nitrate anion, ${\text{NO}}_{3}^{-}$, which means that the nitrate anion will be the acid's conjugate base.

On the other hand, ${\text{SO}}_{4}^{2 -}$, which is the sulfate anion, accepts a proton to form ${\text{HSO}}_{4}^{-}$, the hydrogen sulfate anion, which means that the hydrogen sulfate anion is the base's conjugate acid.

$\overbrace{\textcolor{red}{\text{H")"NO"_ (3(aq)))^(color(purple)("acid")) + overbrace("SO"_ (4(aq))^(2-))^(color(green)("base")) -> overbrace(color(red)("H")"SO"_ (4(aq))^(-))^(color(green)("conjugate acid")) + overbrace("NO"_(3(aq))^(-))^(color(purple)("conjugate base}}}$