# Question c446e

Apr 27, 2016

${p}_{X e} = 462.71$ $m m H g$

#### Explanation:

Dalton's law states that:

p_i/(Σp_i)=n_i/(Σn_i)

where ${p}_{i}$ is the pressure and ${n}_{i}$ are the moles of each individual gas and Σ is the notation of their sum (Σx_i=x_1+x_2+...).

Σp_i=1560 $m m H g$

Σn_i=1.5+2.65+1.75=5.9 $m o l$

By using Dalton's law on $X e$:

p_(Xe)/(Σp_i)=n_(Xe)/(Σn_i)

p_(Xe)=n_(Xe)/(Σn_i)*Σp_i=1.75/5.9*1560# $\frac{\cancel{m o l}}{\cancel{m o l}} \cdot m m H g$

${p}_{X e} = 462.71$ $m m H g$