Question #81259 Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Andrea S. May 1, 2017 #y = x/(sqrt(1-x^2)# Explanation: #y = tan(arcsin x)# Pose #t = arcsin x# so that #sint = x# We have then: #cost = sqrt (1-x^2)# and: #tant = sint/cost = x/(sqrt(1-x^2)# Then: #y = tan(arcsin x) = tan t = x/(sqrt(1-x^2)# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1158 views around the world You can reuse this answer Creative Commons License