# Question #607c0

May 2, 2016

1). $9 \times {10}^{13} J$

#### Explanation:

To find out the required value we need to use the mass energy equivalence relation for energy $E$,

$E = m {c}^{2}$
where $m$ is the mass and $c$ is the velocity of light in vacuum and is taken as $3 \times {10}^{8} m {s}^{-} 1$. Substituting the given numbers
$E = \left(1 \times {10}^{-} 3\right) \times {\left(3 \times {10}^{8}\right)}^{2}$
or $E = 9 \times {10}^{13} J$