# Question 93cfe

Jun 23, 2016

$\approx 27 \times {10}^{\text{-21}} J$

#### Explanation:

If a particle of mass m acts as harmonic osciillator of angular frequency w under a periodic force having force constant k then we have the relation.

$w = \sqrt{\frac{k}{m}}$

Again the zero point energy of the oscillator is

${E}_{0} = \frac{1}{2} \cdot h \cdot w , \text{ h= Planck's constant}$

E_0=1/2*6.626*10^"-34"*sqrt(155/(2.33xx10^"-26")J#

$= 3.313 \cdot {10}^{\text{-21}} \cdot \sqrt{\frac{155}{2.33}} J$
$\approx 27 \times {10}^{\text{-21}} J$