How do you simplify tanx + cosx/(1 + sinx)?

1 Answer
May 9, 2016

(sinx(sinx + 1))/((cosx)(sinx + 1)) + ((cosx)(cosx))/((1 + sinx)(cosx))

(sin^2x + sinx + cos^2x)/((cosx)(sinx + 1))

Applying the Pythagorean identity sin^2x + cos^2x = 1:

(1 + sinx)/((cosx)(sinx + 1))

1/cosx

Applying the reciprocal identity 1/cosx = secx:

secx

Hopefully this helps!