# Question #6f7cd

##### 1 Answer

Oct 3, 2017

The Rayleigh criterion for diffraction-limited vision for the minimum resolvable detail of objects located at a distance

#sintheta_D=1.22lambda/theta_D#

Inserting given values we get

We know that for very small value of

#sintheta~~theta#

#=>theta~~2.44xx10^-4" radian"#

#a=thetaxxD#

Inserting calculated and given values we get

#a=(2.44xx10^-4)xx(10xx10^3)=2.44" m"#