Question #4e291
1 Answer
Explanation:
Hydrochloric acid,
As you can see, every mole of hydrochloric acid will produce one mole of hydronium cations and one mole of chloride anions
The pH of the solution is calculated by taking the negative log base
color(blue)(|bar(ul(color(white)(a/a)"pH" = - log(["H"_3"O"^(+)])color(white)(a/a)|)))
You can express the concentration of the hydronium cations in term of the solution's pH by rewriting the above equation as
log(["H"_3"O"^(+)]) = -"pH"
This will be equivalent to
10^log(["H"_3"O"^(+)]) = 10^(-"pH")
which will give you
color(blue)(|bar(ul(color(white)(a/a)["H"_3"O"^(+)] = 10^(-"pH")color(white)(a/a)|)))
In your case, the solution is said to have a pH of
["H"_3"O"^(+)] = 10^(-4.65)
["H"_3"O"^(+)] = color(green)(|bar(ul(color(white)(a/a)2.24 * 10^(-5)"M"color(white)(a/a)|)))