How do you graph the line #y = -1/3x - 7#?

1 Answer
Feb 7, 2018

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (-1/3 xx 0) - 7#

#y = 0 - 7#

#y = -7# or #(0, -7)#

Second Point: For #x = 3#

#y = (-1/3 xx 3) - 7#

#y = -3/3 - 7#

#y = -1 - 7#

#y = -8# or #(3, -8)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+7)^2-0.075)((x-3)^2+(y+8)^2-0.075)=0 [-20, 20, -15, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (1/3)x + 7)(x^2+(y+7)^2-0.075)((x-3)^2+(y+8)^2-0.075)=0 [-20, 20, -15, 5]}