Question

Question #8ced5

Answer 1

The new temperature is -73 °C.

Explanation:

Given

The volume `V_1` of a gas at a temperature `T_1`.
A second volume `V_2`

Find

The second temperature `T_2`

Strategy

A problem involving two gas volumes and two temperatures must be a Charles' Law problem.

The formula for Charles' Law is

`color(blue)(|bar(ul(color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)|)))" "`

Solution

We can rearrange Charles' Law to get

`T_2 = T_1 × V_2/V_1`

In your problem,

`V_1 = "15 L"`; `T_1 = (327 + 273.15) K = "600.15 K"`
`V_2 = color(white)(ll)"5 L"`; `T_2 = "?"`

∴ `T_2 = "600 K" × (5 cancel("L"))/(15 cancel("L")) = "200 K"`

`"200 K" = "(200 - 273.15) °C" = "-73 °C"`

The new temperature is -73 °C.