Question #5d437

1 Answer
May 27, 2017

b->1/3

Explanation:

There are three groups of people. Let them be g_1"; "g_2"; "g_3
Let the total count be g_t

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One half of the employees earn:

g_1=1/2xxg_t >18000

The remainder at this point is 1/2g_t
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One third of the remainder earn:

g_2->15000<[1/3(1/2g_t)]<18000
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What part of the staff earn less than 15000

This is a question just about fractions

The remainder is " "g_3=[1-1/2-(1/3xx1/2)]g_t

1/2-(1/3xx1/2)

1/2-1/6

3/6-1/6" "=" "2/6" "=" "1/3