Question #5d437

1 Answer
May 27, 2017

Answer:

#b->1/3#

Explanation:

There are three groups of people. Let them be #g_1"; "g_2"; "g_3#
Let the total count be #g_t#

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One half of the employees earn:

#g_1=1/2xxg_t >18000#

The remainder at this point is #1/2g_t#
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One third of the remainder earn:

#g_2->15000<[1/3(1/2g_t)]<18000#
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What part of the staff earn less than 15000

This is a question just about fractions

The remainder is #" "g_3=[1-1/2-(1/3xx1/2)]g_t#

#1/2-(1/3xx1/2)#

#1/2-1/6#

#3/6-1/6" "=" "2/6" "=" "1/3#