A #0.240*mol# quantity of dinitrogen gave #7.8*mol# of ammonia. Does this make sense chemically?

1 Answer
Jun 15, 2016

Answer:

#N_2(g) + 3H_2(g) rarr 2NH_3(g)#

Explanation:

You took #0.240*mol# dinitrogen and got #7.8*mol# of ammonia. Clearly, the problem as stated is incorrect.

The reaction quotient, #Q=([NH_3]^2)/([N_2][H_2]^3)#

Where the concentrations are not at equilibrium. You will have to rejig the figures.