# A 0.240*mol quantity of dinitrogen gave 7.8*mol of ammonia. Does this make sense chemically?

Jun 15, 2016

${N}_{2} \left(g\right) + 3 {H}_{2} \left(g\right) \rightarrow 2 N {H}_{3} \left(g\right)$

#### Explanation:

You took $0.240 \cdot m o l$ dinitrogen and got $7.8 \cdot m o l$ of ammonia. Clearly, the problem as stated is incorrect.

The reaction quotient, $Q = \frac{{\left[N {H}_{3}\right]}^{2}}{\left[{N}_{2}\right] {\left[{H}_{2}\right]}^{3}}$

Where the concentrations are not at equilibrium. You will have to rejig the figures.