# Question fec87

Dec 31, 2017

If you specified the data related to enthalpy and entropy, we could calculate the free energy change via,

DeltaG = DeltaH^° - TDeltaS

But you want to make it hard for me! Let's calculate the enthalpy and entropy of the reaction you specified,

${N}_{2} {O}_{4} \left(g\right) \to 2 N {O}_{2} \left(g\right)$, where

DeltaH° = 58kJ

$\Delta S = \frac{176 J}{K}$

assuming that dinitrogen tetroxide is a gas.

Hence,

DeltaG° = 58*10^3 J - 298K * (176J)/K
therefore DeltaG° = 5.6kJ#