# Question #37542

##### 1 Answer

#### Explanation:

You can find the volume of water needed to dissolve **solubility in water**, which you can find here

https://en.wikipedia.org/wiki/Calcium_carbonate

So, calcium carbonate has a solubility of

This tells you that at that temperature, you can only hope to dissolve **per liter** of water, i.e. a **saturated solution** of calcium carbonate will contain *dissolved* calcium carbonate at

You can thus use the compound's solubility as a *conversion factor* to calculate the volume of water needed to dissolve

#1.00color(red)(cancel(color(black)("g CaCO"_3))) * "1 L water"/(0.013 color(red)(cancel(color(black)("g CaCO"_3)))) = color(green)(|bar(ul(color(white)(a/a)color(black)("76.9 L water")color(white)(a/a)|)))#

The answer is rounded to three **sig figs**.

Therefore, you can say that at