# How do you balance the equation 2C_3H_6O_3+3O_2->6CO_2+6H_2O ?

Jul 2, 2016

#### Answer:

$2 {C}_{3} {H}_{6} {O}_{3} + 6 {O}_{2} \to 6 C {O}_{2} + 6 {H}_{2} O$

#### Explanation:

The given equation is nearly balanced:

$2 {C}_{3} {H}_{6} {O}_{3} + 3 {O}_{2} \to 6 C {O}_{2} + 6 {H}_{2} O$

Counting the elements on each side, we have:

• $6 \times C$ on both sides.

• $12 \times H$ on both sides.

• $12 \times O$ on the left hand side, $18 \times O$ on the right hand side.

So we just need to add $6 \times O = 3 {O}_{2}$ on the left hand side to balance the equation:

$2 {C}_{3} {H}_{6} {O}_{3} + 6 {O}_{2} \to 6 C {O}_{2} + 6 {H}_{2} O$