# Question #1757c

Jun 30, 2016

You should get B) $\left(n - 1\right) \times \left(n - 1\right)$ matrix.
Given $A =$$\left(\begin{matrix}1 & 2 & 3 & 4 \\ 1 & 2 & 3 & 4 \\ 1 & 2 & 3 & 4 \\ 1 & 2 & 3 & 4\end{matrix}\right)$ order $n = 4$
$B =$$\left(\begin{matrix}1 & 2 & 3 \\ 1 & 2 & 3 \\ 1 & 2 & 3\end{matrix}\right)$ of order $n - 1 = 3$