# Question 9a12e

Sep 25, 2016

M(x/2 ; (y-3)/2)

#### Explanation:

The midpoint is found from finding:

"The average of the x-values and the average of the y-values"

As a formula : M((x_1+x_2)/2 ; (y_1+y_2)/2)

From the given points $V \left(- 2 , - 6\right) \mathmr{and} W \left(x + 2 , y + 3\right)$

M((-2+x+2)/2 ; (-6+y+3)/2)

M(x/2 ; (y-3)/2)#

Sep 25, 2016

Midpoint Formula for two points $\left({x}_{1} , {y}_{1}\right) \mathmr{and} \left({x}_{2} , {y}_{2}\right)$ is as follows
$\left(\frac{{x}_{1} + {x}_{2}}{2} , \frac{{y}_{1} + {y}_{2}}{2}\right)$

Something like you're averaging the two points' $x$- and $y$-values.

Inserting given values we get the coordinates of the midpoint as
$\left(\frac{- 2 + \left(x + 2\right)}{2} , \frac{- 6 + \left(y + 3\right)}{2}\right)$
$\implies \left(\frac{x}{2} , \frac{y - 3}{2}\right)$