Question

Question #091e6

Answer 1

`intbcos(theta)dx = x*bcos(theta) + C` or, if you meant to ask for `intbcos(theta)d theta` then the integral is `bsin(theta) + C`.

Explanation:

The `dx` at the end of an integral means that the integral should be performed with respect to `x`. So for an equation like `bcos(theta)` which does not have an `x`, the integral is trivial, we just multiply in an `x` and add the constant.

`intbcos(theta)dx = xbcos(theta) + C`

In case the question was actually meant to be `intbcos(theta)d theta` then the answer is still not too hard.

The integral of `cos(x)` is `sin(x)`. Applying this rule, the answer is easily found:
`intbcos(theta)d theta = bintcos(theta) d theta = bsin(theta) + C`