Question #dbe68

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Answer 1 · 2016-08-22T19:54:12

#=(x+8)/(x-2)#

Excluded values are #x+4#

#(x^2+12x+32)/(x^2+2x-8)#

#=(x^2+8x+4x+32)/(x^2+4x-2x-8)#

#=(x(x+8)+4(x+8))/(x(x+4)-2(x+4))#

#=((x+8)(x+4))/((x-2)(x+4))#

#=((x+8)cancel((x+4)))/((x-2)(cancel(x+4)))#

#=(x+8)/(x-2)#

Excluded values are #x+4#