# What are the exclude values of the expression (64 - 8x)/(8x + 64)?

May 19, 2017

See a solution explanation/process below:

#### Explanation:

We cannot divide by $0$, therefore:

$8 x + 64$ cannot equal 0#.

To find the excluded values set $8 x + 64$ equal to $0$ and solve for $x$:

$8 x + 64 = 0$

$8 x + 64 - \textcolor{red}{64} = 0 - \textcolor{red}{64}$

$8 x + 0 = - 64$

$8 x = - 64$

$\frac{8 x}{\textcolor{red}{8}} = - \frac{64}{\textcolor{red}{8}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{8}}} x}{\cancel{\textcolor{red}{8}}} = - 8$

$x = - 8$

The excluded value is $x = 8$