What are the exclude values of the expression #(64 - 8x)/(8x + 64)#?

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Answer 1 · 2017-05-19T13:22:50

See a solution explanation/process below:

We cannot divide by #0#, therefore:

#8x + 64# cannot equal 0#.

To find the excluded values set #8x + 64# equal to #0# and solve for #x#:

#8x + 64 = 0#

#8x + 64 - color(red)(64) = 0 - color(red)(64)#

#8x + 0 = -64#

#8x = -64#

#(8x)/color(red)(8) = -64/color(red)(8)#

#(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = -8#

#x = -8#

The excluded value is #x = 8#