Question 5716a

Aug 15, 2016

$\frac{\sqrt{a}}{2}$

Explanation:

Here, both x and a >=0.

$y ' = \sqrt{a} - \frac{a}{2 \sqrt{x}}$

At@$x = a , y = 0 , y ' = \sqrt{a} - \frac{a}{2 \sqrt{a}} = \sqrt{a} - \frac{\sqrt{a}}{2} = \frac{\sqrt{a}}{2}$.

The equation of the tangent here is

$y = \frac{\sqrt{a}}{2} \left(x - a\right)$