Question #5db2a

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Answer 1 · 2017-07-03T11:47:34

#1# foot wil remain after #5# cuts.
#a_(n+1)=a_1*r^n# feet will remain after #n# cuts .

1st term is #a_1=243# . Common ratio is #r=1-2/3=1/3#

This is series of geometric progression # (243,81,27,9,3,1..)#

Number of terrms is #n=5+1=6# after #5# cuts

#n# th term is #a_n=a_1*r^(n-1) :. a_6= 243*(1/3)^5=243*1/243=1#foot

#1# foot wil remain after #5# cuts.

#a_(n+1)=a_1*r^n# feet will remain after #n# cuts .[Ans]