# Question #0b292

##### 1 Answer

The volume of the gas will increase by a factor of

#### Explanation:

The idea here is that you can use **Charles' Law** to calculate the change in volume caused by the given change in temperature, provided of course that the pressure **stays constant**.

The mass of nitrogen gas is not relevant here. This mass is equivalent to a number of moles of gas, but since the quantity of nitrogen gas remains **unchanged**, you don't have to worry about exactly *how many* moles you have in there.

So, you know that when pressure and number of moles of gas are **constant**, **volume** and **temperature** have a *direct relationship*.

Simply put, when temperature *increases*, the volume of the gas **Increases** as well. SImilarlly, when temperature *decreases*, the volume of the gas **decreases** as well.

You can thus say that

#color(blue)(|bar(ul(color(white)(a/a)V_1/T_1 = V_2/T_2color(white)(a/a)|)))" "# , where

* absolute temperature* of the gas at an initial state

*of the gas at a final stat*

**absolute temperature**It's *very important* to realize that you're dealing with **absolute temperature**, which is temperature expressed in *Kelvin*, so make sure that you convert your two values before using the equation.

Your goal here is to solve for

#V_1/T_1 = V_2/T_2 implies V_2 = T_2/T_1 * V_1#

Plug in your values to find

#V_2 = ( (273.15 + 20)color(red)(cancel(color(black)("K"))))/((273.15 + 15)color(red)(cancel(color(black)("K")))) * V_1#

#V_2 = 1.073 * V_1#

You can thus say that the volume of the gas will **increase** by a factor of