# Question #26c2d

##### 1 Answer

Sep 27, 2016

#### Answer:

See the Explanation>

#### Explanation:

**Ans. to Q(1) :** To verify whether a set

set

Here, the set

that they are also the elements of the set B.

Accordingly,

**Ans. to Q(2) :**

The complement of

all those elements in NN which are **not** in

Hence,

We may write,

**Ans. to Q(3) :**

Indeed,

In fact, this is the **Defn.** of **Equality of Sets.** #