50 g of sodium azide
From the balanced reaction you can see that from 2 mol of
As 1 mol of any gas occupies a volume of 22,4 L in normal condition (P= 1 atm and T= 273K), 1,05 mol occupy
The volume of nitrogen is C)
The balanced chemical equation is
Step 1. Calculate the moles of
Step 2. Calculate the moles of
Step 3. Calculate the volume of
We aren't given the volume or the temperature, so we will have to make an assumption.
Let's assume NTP (1 atm and 20 °C).
Then we can use the Ideal Gas Law to calculate the volume:
#color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "#
We can rearrange the Ideal Gas Law to get
#V = (nRT)/p#
In this problem,
Note: The answer should have only two significant figures, because that is all you gave for the mass of sodium azide.
However, I calculated to three significant figures, because that is the answer in