# Given the neutral oxide, Mn_3O_4...what are the probable oxidation states of the manganese centres given that the metal expresses ONLY two oxidation states in this species?

Jan 5, 2018

The oxidation number of oxygen, as oxide, is typically $- I I$...and so $3 \times M {n}_{\text{oxidation number}} - 8 = 0$...$M {n}_{\text{average oxidation number}} = + \frac{8}{3}$...and so we gots $2 \times M {n}^{+ I I I} + M {n}^{+ I I}$...
The solid state structure does correspond to a formulation of $M n O \cdot M {n}_{2} {O}_{3}$...the which does reflect the oxidation states we assigned. Capisce?