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Question #465f7

1 Answer

Oct 13, 2016

#f'(x) = -sinx#

Explanation:

#f(x) = (sin^2(x))/(1-cos(x)) #

#= (1-cos^2x)/(1-cosx)#

# = ((1-cosx)(1+cosx))/(1-cosx)#

# = 1+cosx#.

So,

#f'(x) = -sinx#.

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