How do you use the Root Test on the series #sum_(n=1)^oo((n^2+1)/(2n^2+1))^(n)# ?

1 Answer
Oct 16, 2014

Let #a_n=({n^2+1]/{2n^2+1})^n#.

By Root Test,

#lim_{n to infty}root[n]{|a_n|}=lim_{n to infty}root[n]{|({n^2+1}/{2n^2+1})^n|}#

by cancelling out the nth-root and the nth-power,

#=lim_{n to infty}{n^2+1}/{2n^2+1}#

(Note: the absolute value is not necessary since it is already positive.)

by dividing by #n^2#,

#=lim_{n to infty}{1+1/n^2}/{2+1/n^2}={1+0}/{2+0}=1/2<1#

Hence, the series converges.

I hope that this was helpful.