Question #ee1ea Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Binayaka C. Aug 19, 2016 In #[0< x< 360]; x=150^0,330^0# Explanation: #tan(x)=-cot(pi+pi/3) = -cot(180+60)=-cot240=-(1/tan240)=-(1/sqrt3):.x=tan^-1(-1/sqrt3) =-30^0# in #[0< x< 360]; x=150^0,330^0# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 1010 views around the world You can reuse this answer Creative Commons License