# Question #cb310

##### 2 Answers

For problems of this type, you need to first graph, and then shade the solution region using test points.

The parabola

While you graph, make sure that you have a dotted line, since this inequality has the symbol ">" and not "≥".

For the second equation,

Isolating y:

You can now place the y intercept, which is

You can then connect these dots using a complete line, not a dotted one, since the symbol used in this case is

As for the shading, usually for quadratic inequalities I would select test points and for linear inequalities I would shade through logical induction. In

For

Let **Test Point #1 be (0, 0)**

So, we shade inside the parabola.

Once this is done, the solution to the inequality is the region where the two shaded areas overlap.

Here is what you should have in the way of graphing, except your graph should have the parabola as a dotted line (my program can for some reason not draw this properly).

As for points of intersection, I think the graph says it all. A few examples are

Hopefully this helps!

#### Explanation:

Another way, algebraically:

The roots of

Given a restriction on

Note that the restrictions on the

But points such as