If #8sqrt(4z^2 - 43) = 40#, what is the value of #z#?
Assumption: the question is:
This is done in stages. First you have all the terms with z on the LHS of = and all the terms without z on the other side.
Then you manipulate the LHS side until the only thing left is the single z.
Add 43 to both sides giving
Divide both sides by 8. Same as multiply by
Taking the root
divide both side by 2 to get rid of the 2 from
Check: Consider the left hand side only for
Thus LHS=RHS so