# How many atoms exist in a 23*g mass of sodium metal?

Sep 5, 2016

Yes (and sort of no)

#### Explanation:

1 mole of Na = 6.022140857(74)×10^"23" atoms .

Note the use of the word atoms .

1 mole of $N {a}^{+}$ would be 6.022140857(74)×10^"23" ions .

I may seem to be overly pedantic in this, but science is all about accuracy.

The number - 6.022140857(74)×10^"23" - is called the Avogadro constant and you can read more about it on Wikipedia.

Sep 5, 2016

$1 \cdot \text{mole}$ of sodium metal $\equiv$ $6.022 \times {10}^{23}$ atoms NOT ions.

#### Explanation:

$1 \cdot \text{mole}$ of $N {a}^{+}$ $\equiv$ $6.022 \times {10}^{23}$ ions.

Of course we can make ions from atoms and atoms from ions and vice versa.

$N a \left(g\right) \rightarrow N {a}^{+} \left(g\right) + {e}^{-} \left(g\right)$.

Given $22.99 \cdot g$ of metal, there are molar quantities of atoms, ions, and electrons. The given stoichiometry demands this.