Question

Question #4341e

Answer 1

Here's how I do it.

Explanation:

Step 1. Draw the bond-line structure.

We see that there are two chiral carbons (those bearing the `"Cl"` atoms) — they are attached to four different groups.

The maximum number of stereoisomers is `2^n`, where `n` is the number of chiral centres.

There is no internal plane of symmetry, so the number of stereoisomers is `2^2 = 4`.

Step 2. Convert the structure to a wedge-dash formula.

Here the `"C-Cl"` bonds are both wedges.

The four possible combinations are: wedge-wedge, dash-dash, wedge-dash, and dash-wedge.

Step 3. Draw the structures for the three remaining combinations..