Question #59bfc

Sep 8, 2016

I found $1.3 \frac{m}{s} ^ 2$

Explanation:

We assume she starts from rest at $0 k \frac{m}{h}$ so that after¨$6 s$ she is at:
$\frac{27}{3.6} = 7.5 \frac{m}{s}$ (I changed it to be consistent with the time).
Let us use kinematic in:
${v}_{f} = {v}_{i} + a t$
using our initial and final velocities we have:
$7.5 = 0 + 6 a$
and rearranging:
$a = \frac{7.5}{6} = 1.25 \approx 1.3 \frac{m}{s} ^ 2$