# Question #0e34f

Sep 9, 2016

Taking density of water as $1 \frac{g}{m L}$, the mass of 14mL water will be $14 g$

Now molar mass of water$= 18 \frac{g}{m o l}$

So 14 g water contains $\frac{14 g}{18 \frac{g}{m o l}} = \frac{14}{18} m o l$ water.

$\frac{14}{18} m o l$ water will contain $\frac{14}{18} \times 6.023 \times {10}^{23}$ molecules water.

As 1 molecule of water contains 2 atoms of Hydrogen , then number of hydrogen atoms in 14 mL water will be

$= \frac{14}{18} \times 6.023 \times {10}^{23} \times 2 = 9.37 \times {10}^{23}$ atoms