What is the #pH# for a #0.020*mol*L^-1# solution of #HCl(aq)#?

1 Answer
Sep 14, 2016

Answer:

#pH=1.70#

Explanation:

#pH=-log_10[H_3O^+]#

#=# #-log_10(0.02)#, given that we assume hydrochloric acid dissociates completely to give stoichiometric #H_3O^+(aq)#:

#HCl(aq) +H_2O(l) rightleftharpoons H_3O^+ + Cl^-#