Solve #((x+1)/(x+2))+((x+2)/(x+3))+7/2=2# ? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Alan N. Sep 17, 2016 #x~=-1.63841# or #~=-2.79016# Explanation: #((x+1)/(x+2))+((x+2)/(x+3))+7/2=2# #((x+1)(x+3)+(x+2)^2)/((x+2)(x+3)) = -3/2# #2(x+1)(x+3)+2(x+2)^2=-3(x+2)(x+3)# #2(x^2+4x+3) + 2(x^2+4x+4) =-3(x^2+5x+6)# #2x^2+8x+6 + 2x^2+8x+8= -3x^2-15x-18# #7x^2+31x+32=0# Using the quadratic formula: #x=(-31+-sqrt(31^2-4*7*32))/(2*7)# #x=(-31+-sqrt(65))/14# #x~= (-31+-8.06226)/14# #x~=-1.63841# or #-2.79016# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 998 views around the world You can reuse this answer Creative Commons License