# How do you solve for f: f-1+2f+f-3=-4?

First of all, let's sum up all terms involving $f$ on the left hand, and all numbers as well.
The terms involving $f$ are $f + 2 f + f$, which equals $4 f$, while numbers are $- 1 - 3$, which equals $- 4$. So far, we can rewrite our equality as
$4 f - 4 = - 4$.
$4 f - 4 + 4 = - 4 + 4$, which means
$4 f = 0$.
Dividing both sides by 4, we have $f = 0$.